Oxidation potential of 0.1M AgNO3 solution is EAg/Ag+o = −0.8V
EAg+/Ag = EAg+/Ago+0.05911logAg+
EAg/Ag+0 = −0.8V
EAg+/Ag 0 = +0.8V......SRP
∴ EAg+/Ag = +0.8V+0.0591log10−1
= +0.74V
Thus EAg/Ag+Oxidation Potential = −0.74V