Q.

Oxidation state of iron Fe0.93 O is

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a

+2

b

+3

c

+2.15

d

+2.8

answer is C.

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Detailed Solution

Fe0.93O ×by 100 Fe93O100 93×x+100-2=0 x=20093 x=+2.15
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Oxidation state of iron Fe0.93 O is