Oxidation state of oxygen in compounds OF2 and Na2O respectively are
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a
+2, -2
b
-2, +2
c
-2, -1
d
+1, -l
answer is A.
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Detailed Solution
OF2, here EN of fluorine is more than oxygen,So, oxidation state of fluorine = - |and oxidation state of oxygen = + 2In Na2O, oxygen has more electronegative value than sodium,So, oxidation state of oxygen = - 2and oxidation state of Na= +1