First slide

Terms used in complex chemistry

Question

The oxidation state of oxygen in $O_{2} [{PtF}_{6}]$ is

Easy

A

zero
B

-1/2
C

+1
D

+1/2

Solution

$O_{2} [{PtF}_{6}]$ is considered to be formed from $O_{2}^{+}$ and ${[{PtF}_{6}]}^{1 -}$ . In $O_{2}^{+ 1}$ , oxidation state of O is 2x = +1.
$x = + \frac{1}{2}$

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