Q.

The oxidation state of oxygen in O2PtF6 is

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a

zero

b

-1/2

c

+1

d

+1/2

answer is D.

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Detailed Solution

O2PtF6 is considered to be formed from O2+ and [PtF6]1-. In O2+1, oxidation state of O is 2x = +1.x=+12
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