Q.

Oxidation state of oxygen in potassium superoxide is :

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a

-1/2

b

-1

c

-2

d

0

answer is A.

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Detailed Solution

Potassium superoxide = KO2∴ Oxidation state of K + 2 x oxidation state of O = 0∴ +1 + (2 x oxidation state of O) = 0∴ Oxidation state of oxygen =−12So, the correct answer is (1).
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