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Q.

The oxidation state of phosphorous in Ba(H2PO2)2 is

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a

+3

b

+2

c

+1

d

-1

answer is C.

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Detailed Solution

Ba(H2PO2)2+2+[2(+1) + x + 2(-2)]2 = 0+2+[2+x-4]2 = 0+2+2x-4 = 0X = +1Alternate methodH2PO2-2(+1) + X + 2(-2) = -1X = +1

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