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a
+3
b
-3
c
+5
d
Both 2 & 3
answer is D.
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Detailed Solution
Due to Lanthanoid contraction , size increases from Sb to Bi is smallIn 'Bi' nuclear attraction over outermost electrons is more. Thus the paired 'ns' electrons are reluctantto uncouple and participate in bonding . Due to this reason 'Bi' shows an ox. state '+3' (corresponding to ground state)And it is unstable in higher ox. state(+5)Compounds of 'Bi' in '+5' state (except BiF5) are unstable and undergo reduction to form stable compounds with '+3' state'Bi' being a metal rarely shows negative oxidation state (-3)