Q.
The oxidation state rarely shown by Bismuth is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
+3
b
-3
c
+5
d
Both 2 & 3
answer is D.
(Unlock A.I Detailed Solution for FREE)
Detailed Solution
Due to Lanthanoid contraction , size increases from Sb to Bi is smallIn 'Bi' nuclear attraction over outermost electrons is more. Thus the paired 'ns' electrons are reluctantto uncouple and participate in bonding . Due to this reason 'Bi' shows an ox. state '+3' (corresponding to ground state)And it is unstable in higher ox. state(+5)Compounds of 'Bi' in '+5' state (except BiF5) are unstable and undergo reduction to form stable compounds with '+3' state'Bi' being a metal rarely shows negative oxidation state (-3)
Watch 3-min video & get full concept clarity