Q.

The oxidation state of Sulphur in the anions S2O4-2 , SO32− and S2O62−follows the order:

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a

S2O42−

b

S2O42−

c

SO32−

d

S2O62−

answer is B.

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Detailed Solution

S2O62−=+5,SO32−=+4S2O42−=+3
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