Oxidation state of Sulphur in its oxyacid is '+3' (or) '+4' then the correct statement is
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a
Covalency of sulphur is 4
b
Sulphur atom has a lone pair on it
c
Sulphur atom is in I excited state
d
All are correct
answer is D.
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Detailed Solution
I - excited state configuration of 'Sulphur';Represents "+3" (or) "+4" state, tetravalency;Each sulphur atom forms 3σ bonds and one dπ-pπ bond;One lone pair is present on sulphur atom; II - excited state configuration of 'Sulphur'Represents '+5' (or) '+6' state,hexavalency;Each sulphur forms 4 σ bonds and two dπ-dπ bonds;No lone pair on Sulphur atom;+3 -- In I-excited state;+5-- In II-excited state;