The oxidation states of the most electronegative element in the products of the reaction of BaO2 with dilute H2SO4 are

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0 and -1

-1 and -2

-2 and 0

-2 and +1

answer is B.

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Detailed Solution

BaO-12+H2SO-24→BaSO-24 + H2O-12In H2O2 oxygen shows = -1 (peroxide) oxidation state and In BaSO4 oxygen shows = -2 oxidation state.

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