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Q.

Oxidation states of S in anions SO32-, S2O42- and S2O62- follow the order

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a

S2O42−

b

SO32−

c

S2O42−

d

S2O62−

answer is A.

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Detailed Solution

S2O4-2  sulphur oxidation number = 2(x) +4(-2) =-2   therefore x= +3                                                                                                                           SO3-2   sulphur oxidation number =x +3(-2) =-2         therefore x = +4                                                                                                                  S2O6-2   sulphur oxidation number = 2(x) +6(-2) = -2  therefore x = +5
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