The oxidation states of S-atoms in S4O62− from left to right respectively are:O--SIIOIIO-S-S-SIIOIOI-O-

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+6, 0, 0, +6

+3, +1, +1, + 3

+5, 0, 0, +5

+4, +1, + 1, 4

answer is C.

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Detailed Solution

Oxidation state (O,S) of left S-atom =+1 (from O-)+(from +2 of each =O)+0(from-S atom)=+.So the correct answer is 3

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