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Q.

The oxidation states of sulphur in the anions SO32-,  S2O42- and S2O62- follow the order

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a

S2O42- < SO32- < S2O62-

b

S2O32- < S2O42- < S2O62-

c

S2O42- < S2O62- < SO32-

d

S2O62- < S2O42- < SO32-

answer is A.

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Detailed Solution

S2O42-, SO32- andS2O62-  has +3, +4 and +5 oxidation numbers.
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