Oxidation states of Sulphur atoms in Polythionic acid ( H2Sn+2O6 ) are
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
+3 in two sulphur atoms and +2 in ‘n’ sulphur atoms
b
+5 in two sulphur atoms and zero in ‘n’ sulphur atoms
c
+2.5 in ‘n+2’ sulphur atoms
d
+6 in two sulphur atoms and -2 in ‘n’ sulphur atoms
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
All oxo acids of Sulphur are dibasic ;In all oxo acids, Sulphur atom is sp3 hybridized ;All the pi bonds are dπ-pπ bonds;Sulphur atom having 2 sigma bonds, 1 double bond and a lone pair around it has pyramidal arrangement around it ;Sulphur atom having 2 sigma bonds, 1 double bond and a lone pair around will be tetravalent with +4 O.S (or) +3 O.S;Sulphur atom having 2 sigma bonds, 2 double bond and no lone pairs around it has tetrahedral arrangement around it ;Sulphur atom having 2 sigma bonds, 2 double bond and no lone pair around will be hexavalent with +6 O.S (or) +5 O.S;Note : Do not forget to count a sigma bond between Oxygen and Hydrogen in O-H bond ;The two Sulphur atoms with a covalency of six have no lone pairs on them ;The ‘n’ Sulphur atoms with a covalency of two have two lone pairs on each of them ;In the ‘n’ Sulphur atoms with a covalency of two, hybridization of Sulphur is sp3 with two bond pairs and two lone pairs ;