Q.

The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is _____×10−5mol dm−3[ Given : Henry’s law constant = KH=8.0×104k Pa  for O2, Density of water with dissolved oxygen = 1.0 Kg dm−3 ]

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answer is 1389.

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Detailed Solution

P=KHXgas20=8×104Xgasxgas=2.5×10−4Xgas=mm+100018Neglecting amount of gas dissolved when compared with moles of waterm=0.013888=1388.8×10−5=1389×10−5 Molarity (M) ≃ Molality(m)
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The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is _____×10−5mol dm−3[ Given : Henry’s law constant = KH=8.0×104k Pa  for O2, Density of water with dissolved oxygen = 1.0 Kg dm−3 ]