The pH at equivalence point when a solution of 0.01 M CH3COOH is titrated with a solution of 0.01 M NaOH. pKa of CH3COOH is 4.74.

CH3COOH+NaOH⇌CH3COONa+H2OLet acid be = V mLV mL of 0.01 M CH3COOH will require V mL of0.01 M NaOH. But CH3COONa formed will makesolution alkaline due to hydrolysis.CH3COONa+H2O⇌CH3COOH+NaOHCH3COONa=0.012=0.005Musing equation for pH of salt of weak acid and strong base.pH=7+pKa2+logC2=7+4.742+log0.0052=8.22