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Q.

pH of 0.1 (M) BOH (weak base) is found to be 12. The solution at temperature T K will display an osmotic pressure equal to

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a

0.01 RT

b

0.01 (RT)2

c

0.11 RT

d

1.1 RT

answer is C.

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Detailed Solution

pH=12, pOH=14−12=2, [OH−]=10−2OH-=Cα10-2=0.1 αα=0.1i=1+(n−1)α=1+(2−1)×0.1=1.1π=iCRT=1.1×0.1 RT=0.11 RT.
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