First slide

PH of weak acids and weak bases

Question

P^OH of 0.002 M HNO₃. is :

Easy

A

11+log 2
B

11-log 2
C

-3+log 2
D

None of these

Solution

$[H^{+}] = 0.002 M pH = \log 2 \times 10^{- 3} = 3 - \log 2 ∴ pOH = 11 + \log 2$

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