The pair of species with the same bond order is

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O22-,B2

O2+,NO+

NO,CO

N2,O2

answer is A.

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Detailed Solution

O22-(8+8+2=18)=σ1s2,σ*1s2,σ2s2,σ*2s2,σ2pz2,π2px2≈π2py2π*2px2≈π*2py2 Bond order (BO) =Nb-Na2=10-82=1B2(5+5=10)=σ1s2,σ*1s2,σ2s2σ*2s2,π2px1≈π2py1BO=6-42=1 Thus, O22- and B2 have the same bond order.

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