For a particular process when ΔH=60kJ/mole and ΔS=200JKmole−1 then the process is non-spontaneous at

At equilibrium, ΔG=0∴ΔH−TΔS=0ΔH=TΔSTeq=60×103200 =300 KΔG=+ve−T+veProcess is spontaneous when ‘T’ is greater than Teq (300K)Process is non-spontaneous when ‘T’ is lesser than Teq (300K)