First slide

Faraday's Laws

Question

On passing 3F electricity through three cells containing fused Na₂CO₃, fused Cu(NO₃)₂ and fused Al(NO₃)₃, the number of moles of the metals deposited are in the ratio

Easy

A

1:2:3
B

3:2:1
C

6:3:2
D

3:4:2

Solution

Number of moles deposited = $\frac{number of equivalents deposited}{valency (n)}$
Ratio of moles of each metal deposited $= \frac{3}{1} : \frac{3}{2} : \frac{3}{3} = 3 : \frac{3}{2} : 1 = 6 : 3 : 2$

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