PCl3 cannot be prepare by

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white or red phosphorus + limited supply of dry Cl2 gas

white or red phosphorus + SO2Cl2

white phosphorus + limited supply of SOCI2

heating PCl5

answer is B.

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Detailed Solution

P4 (white or red) + 6Cl2 (limited quantity) →∆4PCl3P4 (red or white) + 10SO2Cl2→C4PCl5+10SO2P4white+8SOCl2→ 4PCl3+4SO2+2S2Cl2PCl5→ΔPCl3+Cl2

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