First slide

Alkenes

Question

1-pentene reacts with HCl in presence of benzoyl peroxide to give-----as major product.

Moderate

A

1-chloro pentane
B

2-chloro pentane
C

2,2-dimethyl -1-chloro propane
D

1-chloro-3-methyl butane

Solution

H-Cl bond enthalpy is very high. Peroxide cannot break HCl into free radicals. Thus ionic mechanism is followed.
${CH}_{3} - {CH}_{2} - {CH}_{2} - CH = {CH}_{2} \overset{H^{+}}{\to} {CH}_{3} - {CH}_{2} - {CH}_{2} - \overset{+}{C} H - {CH}_{2} (more stable); {CH}_{3} - {CH}_{2} - {CH}_{2} - \overset{+}{C} H - {CH}_{2} (more stable) \overset{{Cl}^{-}}{\to} {CH}_{3} - {CH}_{2} - {CH}_{2} - CHCl - {CH}_{2} (major);$

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