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2-Pentyne can’t be obtained even as minor by the de-hydrohalogenation of the following with fused soda-amide at 200°C
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a
3,3-dibromopentane
b
2,3-dibromopentane
c
2,2-dibromopentane
d
1,2-dibromopentane
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Correct option is D
All the compounds given here can undergo loss of 2 moles of HBr to form 2-pentyne as the major product. But 1,2-Dibromopentane can form only 1-pentyne.Talk to our academic expert!
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