As per law of mass action, for the reaction, NH4HSs⇌NH3g+H2Sg, ratio of rate constants of forward reaction to rate constant of backward reaction at equilibrium equals to

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NH4HS

pNH3+pH2S

NH3+H2S

NH3H2S

answer is D.

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Detailed Solution

Solid=1, thus NH4HS=1; Keq=KfKb; Kc=NH3H2S; Kp=pNH3.pH2S ;

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