The percentage by volume of C3H8 in a gaseous mixture of C3H8, CH4. and CO is 20. When 100 mL of the mixture is burnt in excess of O2, the volume of CO2 produced is:

100mL gaseous mixture contain 20 mL C3H8So, volume of CH4 and CO=(100 -  20) = 80 mLC3H8+5O2⟶3CO2+4H2OCH4+2O2⟶CO2+2H2OCO+12O2⟶CO280 mL (CH4 and CO) will produce 80 mL CO2C3H8 will produce = 3 x 20 = 60 mLTotal CO2 produce = 80 +60  = 140