The percentage of H2 in the hydride of an element having equivalent weight 11.5 is:
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
7.06
b
8.06
c
4.03
d
12.09
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Eq. wt. of element = 11.5; let wt. of metal =x g;wt. of element = 100 - x g; Eq. wt. of H2=1.008.We know that: Wt. of element Wt. of hydrogen = Eq. wt. of metal Eq. wt. of H2(=1.008)or 100−xx=11.51.00811.5x=100.8−1.008x ; 12.508x=100.8∴ x=100.8/12.508=8.06∴ Percentage of H2=8.06%