Percentage of Se in peroxidase anhydrase enzyme is 0.5% by weight (at. wt. = 78.4), then minimum molecular weight of peroxidase anhydrase enzyme is
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a
1.568 × 103
b
15.68
c
1.568 × 104
d
2.136 × 104
answer is C.
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Detailed Solution
Suppose the mol. wt. of enzyme = xIn 100 g of enzyme, wt. of Se = 0.5 g∴ In x g of enzyme wt. of Se=0.5100 × xHence 78.4 = 0.5 × x100∴ x=15680=1.568 × 104