The percentage weight of Zn in white vitriol (ZnSO4. 7H2O) is approximately equal to (Zn = 65, S = 32, O = 16, and H = 1)

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33.65

32.56

23.65

22.65

answer is D.

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Detailed Solution

The molar mass of white vitriol = (65+32+4x16+7x 18)g = 287g.1 mol of white vitriol (287g) contains 1 mol of Zn atoms (65 g).∴%Zn=65g287g×100=22.65

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