A perfect gas undergoes a reversible adiabatic expansion from (300 K,200 atm) to (90 K,10 atm). Find the atomicity of gas.
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answer is 1.
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Detailed Solution
For reversible adiabatic processP11−γ⋅T1γ=P21−γ⋅T2γT1T2=P2P11−γγ;30090=102001−γγ103=1201−γγ;log103=1−γx⋅log1201−γγ=0.5229−1.301=−0.41γ=0.6⇒γ=1.66Atomicity =1