The pH of a buffer solution is 4.745. When 0.044 mole of Ba(OH)2 is added to 1 lit. of the buffer, the pH changes to 4.756. Then the buffer capacity is

0.044 mol of Ba(OH)2 = 0.044 x 2 mol of OH-When 0.088 mol of OH- is added, change in PH                                                 = (4.756 - 4.745)                                                 = 0.011 Conversely,0.011 change of PH occurs when moles of OH- added = 0.088 mol1 change of PH occurs when moles of OH- added =0.0880.011×1=8mol