First slide

Buffer Capacity

Question

The pH of a buffer is 6.745. When 0.01 moles of NaOH is added to 1 litre of it, the pH changes to 6.832. Its buffer capacity is

Easy

A

0.187
B

0.115
C

0.076
D

0.896

Solution

Buffer capacity
$= \frac{No . of moles of base added / litre of buffer}{Change in pH}$
$= \frac{0.01}{(6.832 - 6.745)} = \frac{0.01}{0.087} = 0.115$

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