The pH of a dibasic acid is 3.699. Its molarity is

The question does not provide dissociation constants values and so we will consider it to be a strong acid.H2A→2H++AM-2PH = 3.7⇒ PH = 4 - 0.3 = 4 - log 2⇒ [H+] = 2 x 10-4Na=2×10-4 N ; Ma=Na2=10-4 M ;