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Q.

The pH of 0.5 M aqueous solution of HF  Ka=2 × 10-4 is

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a

2

b

4

c

6

d

10

answer is A.

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Detailed Solution

H+=CKa = 0.5 × 2 ×10-4  =10-2 MpH=-log10 H+=-log 10-2=2
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