Q.

pH of 0.05 M calcium acetate solution (pKa = 4.74) is

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a

8.72

b

8.87

c

7.00

d

1.30

answer is B.

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Detailed Solution

CH3COO2Ca⇌2CH3COO−+Ca2+ CH3COO−+H2O⇌CH3COOH+OH− Solution is alkaline due to hydrolysis of CH3COO− CH3COO−=0.05×2=0.10M pH=7+pKa2+log⁡C2=7+2.37+−12=8.87
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