Q.
pH of 0.05 M calcium acetate solution (pKa = 4.74) is
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a
8.72
b
8.87
c
7.00
d
1.30
answer is B.
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Detailed Solution
CH3COO2Ca⇌2CH3COO−+Ca2+ CH3COO−+H2O⇌CH3COOH+OH− Solution is alkaline due to hydrolysis of CH3COO− CH3COO−=0.05×2=0.10M pH=7+pKa2+logC2=7+2.37+−12=8.87
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