pH of a 0.1 M monobasic acid is found to be 2. Hence, its osmotic pressure at a given temperature T K is
0.1RT
0.11RT
1.1RT
0.01RT
pH=2 H⊕=0.01 M=Cx=0.1x x=0.1 i=1+x=1.1 π=inVRT=iMRT=1.1×0.1RT=0.11RT