pH of a 0.1 M monobasic acid is found to be 2. Hence, its osmotic pressure at a given temperature T K is

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0.1RT

0.11RT

1.1RT

0.01RT

answer is A.

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Detailed Solution

pH=2 H⊕=0.01 M=Cx=0.1x x=0.1 i=1+x=1.1 π=inVRT=iMRT=1.1×0.1RT=0.11RT

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