First slide

Salt hydrolysis :

Question

The pH of 0.02 M ${NH}_{4} Cl (aq .) ({pK}_{b} = 4.73)$ is equal to

Easy

A

3.78
B

4.73
C

5.48
D

7.00

Solution

Ammonium chloride is salt of strong acid and weak base, solution is acidic.
$pH = \frac{1}{2} [{pK}_{w} - {pK}_{b} - \log C] = \frac{1}{2} [14 - 4.73 - \log 0.02] = \frac{1}{2} [14 - 4.73 + 1.698] = 5.48$

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