The pH of 0.02 M NH4Cl (aq.) pKb = 4.73 is equal to

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3.78

4.73

5.48

7.00

answer is C.

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Detailed Solution

Ammonium chloride is salt of strong acid and weak base, solution is acidic.pH=12 pKw- pKb - log C = 12 14-4.73-log 0.02 = 12 14-4.73+ 1.698 = 5.48

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