pH of a mixture of 1 M benzoic acid (pKa, = 4.20) and 1 M sodium benzoate is 4.5. In 300 mL buffer, benzoic acid is

Q.

pH of a mixture of 1 M benzoic acid (pKa, = 4.20) and 1 M sodium benzoate is 4.5. In 300 mL buffer, benzoic acid is

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a

200 mL

b

150 mL

c

100 mL

d

50 mL

answer is C.

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Detailed Solution

If benzoic acid = x mL x millimoles sodium benzoate=(300−x)mL=(300−x) millimoles pH=pKa+log⁡ [sodium benzoate] [benzoic acid] 4.5=4.2+log⁡300−xx 300−xx=2 x = 100 mL

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