First slide
PH of strong acids and strong bases
Question

The pH of 40 ml of a 0.02 M HCl will not be changed by adding

Moderate
Solution

Final concentration of H+ ions,

[H+] =

\frac{40\times 0.02+36\times 0.02}{40+36}=\frac{0.8+0.72}{76}
=\frac{1.52}{76}

Initial  PH = 2-log2 = 1.7

Final  PH = 2-log2 = 1.7

 

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