The pH of a 0.1 molar solution of the acid HQ is 3. The value of the ionization constant, Ka of the acid is

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3 × 10-1

1 × 10-3

1 × 10-5

1 × 10-7

answer is C.

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Detailed Solution

HQ=H+ + Q-H+ = KaC by Ostwald's dilution lawH+ = 10-pH= 10-3 M; C = 0.1 MThus, 10-3= Ka× 0.110-6= Ka× 0.1∴ Ka = 10-5

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