Q.
The pH of a sample of KOH solution is 12.3979. The weight of solid KOH of 70% pure required to prepare 2.5 lit of this solution is
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a
3.5 g
b
5 g
c
8 g
d
6 g
answer is B.
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Detailed Solution
POH = 14 - 12.3979 ~ 1.6[OH-] = 2.5 x10-2Let us consider, w g of KOH is required70×w100×56×2.5=2.5×10-2⇒ w = 5
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