The pH of a solution formed by mixing 10 mL of 0.1 M NaH2PO4 and 20 mL 0.1 M Na2HPO4 would be (Given pK1=2.2, pK2=7.2, log2=0.3 )

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answer is 0007.50.

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Detailed Solution

This is a buffer solution where H2PO4− acts as the acid and NaH2PO4 is the salt ∴pH=pK2+logH2PO4−⇒7.2+log⁡2⇒7.50

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