The pH of a solution formed by mixing 10 mL of 0.1 M H2SO4 and 10 mL of N10 KOH is
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answer is 1.
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Detailed Solution
Milliequivalents of H+=10×0.1×2=2 Milliequivalent of OH−=10×110=1 Since. meqof H+>meq of OH−thus the rosulting solution should be acidic. Normality of solution =2−120=120=0.05N Molarity of the resulting solution =2×0.05=0.1 pH of the solution =−logH+=−log(0.1) =−log10−1=1