Q.

pH of a solution of 10 ml. 1 N sodium acetate and 50 ml 2 N acetic acid Ka = 1.8 ×  10-5 is approximately

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a

4

b

5

c

6

d

7

answer is A.

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Detailed Solution

pH=pKa + log SaltAcid  ; [Salt] =101000×1=10-2 ;[Acid] =501000×2 =10-1 pH =-log 1.8×10-5 + log 10-210-1 =-log 1.8 + 5+log 10-1 =-0.2553+5-1=3.7447  or  = 4
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