First slide

Acidic buffer

Question

pH of a solution of 10 ml. 1 N sodium acetate and 50 ml 2 N acetic acid $(K_{a} = 1.8 \times 10^{- 5})$ is approximately

Moderate

A

4
B

5
C

6
D

7

Solution

$pH = {pK}_{a} + \log \frac{[Salt]}{[Acid]}; [Salt] = \frac{10}{1000} \times 1 = 10^{- 2}; [Acid] = \frac{50}{1000} \times 2 = 10^{- 1} pH = - \log (1.8 \times 10^{- 5}) + \log \frac{[10^{- 2}]}{[10^{- 1}]} = - \log 1.8 + 5 + \log 10^{- 1} = - 0.2553 + 5 - 1 = 3.7447 or = 4$

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