Q.

PhC≡CH Piperidine I2→ Product (A)Product (A) is:

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a

PhC(I)=CHI

b

PhCH(I)CH2I

c

IC≡CH

d

PhC≡CI

answer is D.

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Detailed Solution

Piperidine is a strong base so it can abs tract terminal H-atom.PhC≡C−H;⟶ Piperdine Ph−C≡C⊖⟶I2PhC≡C−I        (A)
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PhC≡CH Piperidine I2→ Product (A)Product (A) is: