Q.

Phosphorous exhibits highest oxidation state in

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a

PH3

b

H3PO3

c

Ca3(PO4)2

d

H3PO2

answer is C.

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Detailed Solution

PH3 X + 3(+1) = 0X = -3H3PO33(+1) + X + 3(-2) = 0X = +3Ca(PO4)23(+2) + 2(X) + 8(-2) = 0X = +5H3PO23(+1) + X + 2(-2) = 0X = +1
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