Q.
In a Photo electric effect experiment, A metal ‘X’ is irradiated by two incident radiations in two different experiments. If the ratio of incident frequencies is 1:2 and the ratio of kinetic energy of photo electrons is 1:3. Then the correct relation is (where ν1, ν2 are incident frequencies in experiment one and two respectively and ν0 is the threshold frequency of the metal ‘X’)
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a
3ν0=ν1
b
2ν0=ν1
c
ν0=ν1
d
1.5ν0=ν1
answer is B.
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Detailed Solution
For the same metal, work function(W) remains constant;hν1=hν0+K.E1....1 hv2=hν0+K.E2.....(2) K.E1K.E2=ν1-v0ν2-v0; 13=ν1-ν02ν1-ν0; 2ν1-ν0=3(ν1-ν0) 2ν0=ν1
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