In a photoelectric experiment, kinetic energy of photoelectrons was plotted aganist the frequency of incident radiation (v), as shown in figure. Which of the following statements is correct?

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The threshold frequency is v1

The slope of this line is equal to Planck's constant

As the frequency of incident radiation increase kinetic energy of photoelectrons decreases

It is impossible to obtain such a graph.

answer is B.

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Detailed Solution

KE = hv- hvºKE(y) = hv - hvºA straight line graph with a positive slope (h) and a negative y - intercept (-hvº).

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