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Q.

A photon of 300 nm is absorbed by a gas, which the re-emits two photons. One re-emitted photon has a wavelength of 400 nm. Calculate the energy of the other re-emitted photon.

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a

1.656×10−19J

b

1.892×10−20J

c

1.656×10−24J

d

1.76×10−20J

answer is A.

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Detailed Solution

Etotal=hcλ=6.626×10−34Js×3×108ms−1300×10−9m =6.626×10−19JE1=6.626×10−34Js×3×108ms−1400×10−9mE2=(Etotal−E1) =6.626×10−19×(1−34)=14×6.626×10−19J =1.656×10−19J

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A photon of 300 nm is absorbed by a gas, which the re-emits two photons. One re-emitted photon has a wavelength of 400 nm. Calculate the energy of the other re-emitted photon.