A piston filled with 0.04 mole of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.00C. As it does so, it absorbs 208 J of heat. The values of q and W for the process will be (R = 8.314 J/mol K, ln 7.5 = 2.01)
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a
q=+208 J, W = -208J
b
q=-208 J, W = -208J
c
q=-208 J, W = +208J
d
q=+208 J, W = +208J
answer is A.
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Detailed Solution
As the process is carrying out at constant temperature, therefore this type of expansion is called isothermal reversible expansion, for which, ∆U=0. Hence, q=-W i.e., heat absorbed by the system is equal to the work done by the system.Thus, q = + 208 J W= - 208 J